[스파르타] 99클럽 2기 코테스터디 33일차 TIL / leet 869

Leetcode: 869. Reordered Power of 2 (링크)

 

869. Reordered Power of 2

 

class Solution:
    def reorderedPowerOf2(self, n: int) -> bool:
        num = sorted(str(n))
        for i in range(32):
            current_num = sorted(str(2**i))
            if num == current_num:
                return True
        return False

오늘 미들러 풀이 끝!

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참고한 블로그: https://leetcode.com/problems/reordered-power-of-2/solutions/2482867/python-simple-python-solution-using-two-different-approach/